Where Quant meets Logic
If we define P(x)=1+x+x^2+..+x^6. Then what will be the remainder when P(x^7) is divided by P(x)?a) 0 b) 1 c) 7 d) 49 e) none of theseI am getting answer as none of these(2)Assuming x>1P(x^7)= x^7+1x^7+1 % (1+x+x^2+..+x^6)Multiply both N and D by (x-1)[(x-1)*(x^7+1)]%(x^7-1)Now, x-1 % (x^7-1) = (x-1)and(x^7+1)%(x^7-1) = 2Hence, [(x-1)*(x^7+1)]%(x^7-1) = 2*(x-1)Since we multiplied N and D by (x-1) in begining divide R by (x-1) to get original R.Hence R=2Is it right???
@ Amit,the answer is 7!use remainder theorem
can u plzz solve dis still not getn it
If we define P(x)=1+x+x^2+..+x^6. Then what will be the remainder when P(x^7) is divided by P(x)?
ReplyDeletea) 0 b) 1 c) 7 d) 49 e) none of these
I am getting answer as none of these(2)
Assuming x>1
P(x^7)= x^7+1
x^7+1 % (1+x+x^2+..+x^6)
Multiply both N and D by (x-1)
[(x-1)*(x^7+1)]%(x^7-1)
Now, x-1 % (x^7-1) = (x-1)
and(x^7+1)%(x^7-1) = 2
Hence, [(x-1)*(x^7+1)]%(x^7-1) = 2*(x-1)
Since we multiplied N and D by (x-1) in begining divide R by (x-1) to get original R.
Hence R=2
Is it right???
@ Amit,
ReplyDeletethe answer is 7!
use remainder theorem
can u plzz solve dis still not getn it
ReplyDelete