Where Quant meets Logic
Answer is 45 degrees???
yupp
Since no constraints are given, we take the triangle to be isos rt. triangle.So AC=BCNow, join CM and CNIn triangle, BMC, <CBM=45so, <BCM=<BMC=67.5so, <ACM=22.5similarly <BCN=22.5So, <MCN=90-22.5-22.5=45deg
well we can do without the assumption too, its a simple geometry problembut well done
Answer is 45 degrees???
ReplyDeleteyupp
ReplyDeleteSince no constraints are given, we take the triangle to be isos rt. triangle.
ReplyDeleteSo AC=BC
Now, join CM and CN
In triangle, BMC, <CBM=45
so, <BCM=<BMC=67.5
so, <ACM=22.5
similarly <BCN=22.5
So, <MCN=90-22.5-22.5=45deg
well we can do without the assumption too,
ReplyDeleteits a simple geometry problem
but well done