When the mean, median and mode of the list 10,2,4,2,5,2,and x are arranged in increasing order, they form a non-constant arithmetic progression. FInd the sum of all such real x?
Nice one. Now the mode is 2 is quite evident. Median depends on the value of x that is if 2<x4 then 4 is the median. Mean = (25+x)/7 So now consider 2<x4, then 4 is the median so the mean should be 6. So x=17 So the sum of values is 17+3=20
hmm I thought its a typo but it's not getting typed at all..regarding median, If x lies b/w 2 and 4, then median is x and if x is greater than 4 the median is 4.
Option E 17 +3 = 20 mode=2 If x is the median 2,2,2,x,4,5,10 value of x comes to be three When x considered to be greater than 4 , its value 17. As mode , median ,mean are in A.p. x cannot be placed in first 4 places as that would make mode and median equal.
Nice one.
ReplyDeleteNow the mode is 2 is quite evident.
Median depends on the value of x that is if 2<x4 then 4 is the median.
Mean = (25+x)/7
So now consider 2<x4, then 4 is the median so the mean should be 6. So x=17
So the sum of values is 17+3=20
Typo
ReplyDeleteMedian is x if 2<x4
hmm I thought its a typo but it's not getting typed at all..regarding median,
ReplyDeleteIf x lies b/w 2 and 4, then median is x and if x is greater than 4 the median is 4.
Option E
ReplyDelete17 +3 = 20
mode=2
If x is the median
2,2,2,x,4,5,10
value of x comes to be three
When x considered to be greater than 4 , its value 17. As mode , median ,mean are in A.p. x cannot be placed in first 4 places as that would make mode and median equal.
x cannot be placed before 2 in the first 4 places when arranged in an increasing order and cannot be equal to 2.
ReplyDelete