Where Quant meets Logic
Let P(x)=ax^4 +bx^3+cx^2+dx+e be a polynomial with all integer coefficients and a=1. If√2+√5 is one of the roots of P(x)=0 , which of the following can be the value of |(b+c+d+e)|?
1) 103
2) 89
3) 63
4) 23
5) 5
is the answer d) 23|(b+c+d+e)|=23b=d=0, c= -18 e=41correct me??
aakaj its 5. yaar
hi Varun,correct me...this is how we are solving...put the value of x in the expression and then equate p(x) to zero....compare the terms with zero....the values which i get are b=0, d=0, e=41 and c=-18.... (correct me if these values are incorrect)...did a recalculation...not sure where i went wrong :(
4.The values are b=0,c=-14,d=0 and e=9..The equations are28+2c=011b+d=017b+d=089+e+7c=0Answer choice e)
is the answer d) 23
ReplyDelete|(b+c+d+e)|=23
b=d=0, c= -18 e=41
correct me??
aakaj its 5. yaar
ReplyDeletehi Varun,
ReplyDeletecorrect me...this is how we are solving...put the value of x in the expression and then equate p(x) to zero....compare the terms with zero....
the values which i get are b=0, d=0, e=41 and c=-18.... (correct me if these values are incorrect)...
did a recalculation...not sure where i went wrong :(
4.The values are b=0,c=-14,d=0 and e=9..The equations are
ReplyDelete28+2c=0
11b+d=0
17b+d=0
89+e+7c=0
Answer choice e)