hi guys..i know its out of place but i din't know where to post it..so i m writing it here..i have a question on probability..it goes as.. please help me solve it..n if its not the right place to ask it..tell me where should i post it..
There are 5 fruits -Banana,Apple,Orange,Pear and Mango-which are to be served among six boys.If no fruit can be served to more than one boy,find the probability that all the five fruits were served to exactly three boys such that each of the three boys gets at least one fruit.
is it 1
ReplyDeleteOnly two integer values of n 1 and 3 are the solutions...
ReplyDeleteAns option c....
answer option C is right
ReplyDeleteonly 1 nd 3 so c
ReplyDeletei think its e....we can have any no. of n which even.
ReplyDeleteoohh sory i got the qyestion wrong...i thought it is
ReplyDelete(2^n+1)^n/2
Clearly n = 1 and n = 3 satisfies the condition but now we have to prove that 2^n + 1 will never be a factor of n*n for n >3.
ReplyDeleteI am clueless here ??
What about n=9
ReplyDeletehi guys..i know its out of place but i din't know where to post it..so i m writing it here..i have a question on probability..it goes as..
ReplyDeleteplease help me solve it..n if its not the right place to ask it..tell me where should i post it..
There are 5 fruits -Banana,Apple,Orange,Pear and Mango-which are to be served among six boys.If no fruit can be served to more than one boy,find the probability that all the five fruits were served to exactly three boys such that each of the three boys gets at least one fruit.
answer choices--
1. 5/8
2. 25/54
3. 55/108
4. 175/324
5. 125/324
i posted the previous question..can somebody tell me where to post it
ReplyDelete