Solution ! factors are of the form (n-1)/2 , (n-1)/3 ,(n-1)/4, (n-1)/5.... They might be integer or not....but if integers they are the factors in descending order...
Highest possible sum= (n-1)/2 + (n-1)/3 + (n-1)/4 =13(n-1)/12 > (n-1) Second highest = (n-1)/2 + (n-1)/3 + (n-1)/5= 31(n-1)/30 Next highest sum = (n-1)/2 + (n-1)/4 + (n-1)/5 = 19(n-1)/20 n=13 31(n-1)/30=n => n=31
Solution !
ReplyDeletefactors are of the form (n-1)/2 , (n-1)/3 ,(n-1)/4, (n-1)/5....
They might be integer or not....but if integers they are the factors in descending order...
Highest possible sum= (n-1)/2 + (n-1)/3 + (n-1)/4 =13(n-1)/12 > (n-1)
Second highest = (n-1)/2 + (n-1)/3 + (n-1)/5= 31(n-1)/30
Next highest sum = (n-1)/2 + (n-1)/4 + (n-1)/5 = 19(n-1)/20 n=13
31(n-1)/30=n => n=31
so n=13,31
hence sum 31+13=44
option c)