Let S be the set of five-digit numbers formed by the digits 1, 2, 3, 4 and 5,
using each digit exactly once such that exactly two odd positions are occupied
by odd digits. What is the sum of the digits in the rightmost position
of the numbers in S?
a. 228 b. 216 c. 294 d. 192 e. None of these
sir
ReplyDeletedo u provide solns for problem of the day??
ans is b
ReplyDeleteplz tell
i m also getting (e).
ReplyDelete_ _ _ _ _
1 2 3 4 5
odd even
if we fix one odd and one even no. at 2nd and 4th position,
2odds and 1 even are left, which have to be filled up at the odd places.
i.e. 3C1 * 2C1 * 2! * 3! = 72.
i.e. 12 * (1+2+3+4+5) = 180
is it 216(B)??
ReplyDeleteplz give da answer...
Sorry, for being late in replies.
ReplyDeleteThe answer is option B) 216!
Good luck !
can any1 explain how
ReplyDelete