Where Quant meets Logic
the answer is option (B) 1coz..d number shud in d form of 11x^2...aa=11..den bb must be in d form a0b=704...simply (88)^2=7744
yeah rightit came in CAT 2007
There is a neat trick to it.(25±x)², (50±x)², (100±x)² have last two digits of the same form.now only the square of 12 has last two digits which are samehence, the squares of 12, 38, 62 and 88 have 44 as last two digits.only 88 is a multiple of 11.Hence 1 solution
thnx rahul
yes... use wht implex has used.... but one can go one step further here... :)wld post it sometime.... i call it concept of sweet squares :)
the answer is option (B) 1
ReplyDeletecoz..d number shud in d form of 11x^2...
aa=11..
den bb must be in d form a0b=704
...
simply (88)^2=7744
yeah right
ReplyDeleteit came in CAT 2007
There is a neat trick to it.
ReplyDelete(25±x)², (50±x)², (100±x)² have last two digits of the same form.
now only the square of 12 has last two digits which are same
hence, the squares of 12, 38, 62 and 88 have 44 as last two digits.
only 88 is a multiple of 11.
Hence 1 solution
thnx rahul
ReplyDeleteyes... use wht implex has used.... but one can go one step further here... :)
ReplyDeletewld post it sometime.... i call it concept of sweet squares :)