Where Quant meets Logic
option (b) 1m = 2^2*3^2n = 2*3*5^2
the solution is incorrect, please try again.
answer is option C 2 ordered pairs are possibleis it right?
Yeah that's correct
hmmm wellm=2^2*3^2n=2*3 am forgetting the 5 for now...see that for gcd to be 2^2*3^2 this is only possi when n^2=this valueand 2^4,3^4 to be lcm means m^2 is this5 can oscillate between m or nhence 2 such pairs... one m=2^2*3^2*5^3 , n=2*3and once m=2^2*3^2 , n=2*3*5^2
That's right! 2 solutions
option (b) 1
ReplyDeletem = 2^2*3^2
n = 2*3*5^2
the solution is incorrect, please try again.
ReplyDeleteanswer is option C
ReplyDelete2 ordered pairs are possible
is it right?
Yeah that's correct
ReplyDeletehmmm well
ReplyDeletem=2^2*3^2
n=2*3
am forgetting the 5 for now...
see that for gcd to be 2^2*3^2 this is only possi when n^2=this value
and 2^4,3^4 to be lcm means m^2 is this
5 can oscillate between m or n
hence 2 such pairs... one m=2^2*3^2*5^3 , n=2*3
and once m=2^2*3^2 , n=2*3*5^2
That's right! 2 solutions
ReplyDelete