Tuesday, October 4, 2011

Problem of the Day 4th Oct 2011

Find x and y, where the variables are natural numbers:

\frac{xy + y}{x + y} = \frac{15}{7}
\frac{x^2 + y}{2x + y} = \frac{19}{11}
Posted by Unknown at 12:10 AM
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3 comments:

  1. AnonymousOctober 4, 2011 at 6:34 PM

    X=4, Y=3.

    ReplyDelete
  2. AnonymousOctober 5, 2011 at 9:51 PM

    is x=4 and y=3 ?
    i got tht from xy+y=15
    y(x+1)=15
    15 can be written as 15.1 or 3.5
    15.1 is not possible
    3.5 is possible
    now by observing we can say that x=4 and y=3

    ReplyDelete
  3. UnknownOctober 5, 2011 at 9:57 PM

    yeah that's right!!

    ReplyDelete

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