i would like to clearify that its the fermat rule that x^n + y^n = z^n...n>=3 has no sloution...else we can solve it by jst hit n trial and reach the solution
Fermat's last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.
intuitively, the fourth powers are 1,16,81,256,... etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0
choice A) 0 ??
ReplyDeleterahul,can u tell the solution of this question
ReplyDeleteit's the fermat's last theorem.And no one till date has been able to prove this.
ReplyDeletex^n + y^n = z^n for n>2 (does not hold).
answer : 0
ReplyDeleteyodha' sol sounds correct .
but in case a person isnot aware of fermat's last theorem then what ??
the solution is right..
ReplyDeletewe do not have a perfect solution for this question.
but intutively we can solve this
clearly 0 is a solution
ReplyDeletei would like to clearify that its the fermat rule that
ReplyDeletex^n + y^n = z^n...n>=3 has no sloution...else we can solve it by jst hit n trial and reach the solution
Fermat's last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.
ReplyDeleteIn Fermat's last theorem n is integer. And it has been proven in 1993 by Andrew Wiles and Richard Taylor.
ReplyDeleteintuitively, the fourth powers are 1,16,81,256,... etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0
ReplyDelete