Thursday, July 16, 2009

Problem of the day 17.07.09

Find the area of right angle triangle whose inradius is 4 and circumradius
is 10?
a) 28                   b) 56                    c) 96                     d) 192                   e) none of these

9 comments:

  1. Is the length of the altitutude (drawn to the hypotenuse) = 1/2(length of hypot.?)
    if so..the hyp=28..is that correct??

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  2. ans is 96
    rahul sir i met you once in CL,you gave lecture on better preparation in gagan sir's class.
    you are doing great job..i owe much to your lessons/concepts
    thank you
    shivam

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  3. Shivam

    I am sure you are mistaking me for someone else.
    I am not aware of any gagan sir and have never been to a Cl class

    ReplyDelete
  4. how to solve this problem

    ReplyDelete
  5. the smallest right triangle is 345
    with inradius 1 and circumradius 2.5
    what we need is a triangle which has four times the given values
    hence the area will be 16 times that of the given triangle
    hnce 16x6=96

    ReplyDelete