Saturday, October 1, 2011

Problem of the day 1 oct 2011

In 3-dimensional space, there are 3 rays leaving point P. Any pair of 2 rays make a 60 degree angle with each other in their respective planes. Points AB, and C are situated on the rays (one per ray) such that PAPB, and PC are all integers, and PA<PB<PC. if PC=2010 and PB is odd, then determine the value of PA if \angle ABC = 90^{\circ}.






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